The end product (C) of the following reaction | vedclass

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(A) $1$. The starting material is cyclopentadiene. Reaction with $HCl$ undergoes electrophilic addition to form $3-$chlorocyclopentene $(A)$.$2$. Trea

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(A) $1$. The starting material is cyclopentadiene. Reaction with $HCl$ undergoes electrophilic addition to form $3-$chlorocyclopentene $(A)$.$2$. Treatment of $3-$chlorocyclopentene with $NaHCO_3/H_2O$ performs a nucleophilic substitution (hydrolysis) to yield $3-$cyclopentenol $(B)$,which has the molecular formula $C_5H_8O$.$3$. Finally,oxidation of the secondary alcohol $3-$cyclopentenol with $Na_2Cr_2O_7$ (a strong oxidizing agent) yields $3-$cyclopentenone $(C)$.

The end product $(C)$ of the following reaction is:

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