Energy of 10 non-rigid diatomic molecules at | vedclass

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Question

(D) For a non-rigid diatomic molecule, the degrees of freedom $(f)$ include $3$ translational, $2$ rotational, and $2$ vibrational modes.Thus, $f = 3

Vedclass · Accepted Answer

$35 \,K_{B} T$

Vedclass · Answer

(D) For a non-rigid diatomic molecule, the degrees of freedom $(f)$ include $3$ translational, $2$ rotational, and $2$ vibrational modes.Thus, $f = 3 + 2 + 2 = 7$.The energy of one molecule is given by $U = \frac{f}{2} K_B T$.Substituting $f = 7$, the energy of one molecule is $U = \frac{7}{2} K_B T$.For $10$ such molecules, the total energy is $E = 10 	imes \frac{7}{2} K_B T = 35 K_B T$.

Energy of $10$ non-rigid diatomic molecules at temperature $T$ is:

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