Equal amounts of two gases of molecular weigh | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given, total pressure of the mixture $(P_{total}) = 1.1 \ atm$. Let the mass of each gas be $m$. Moles of lighter gas $(n_1) = \frac{m}{4}$. Moles

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(D) Given, total pressure of the mixture $(P_{total}) = 1.1 \ atm$. Let the mass of each gas be $m$. Moles of lighter gas $(n_1) = \frac{m}{4}$. Moles of heavier gas $(n_2) = \frac{m}{40}$. Total moles $(n_{total}) = \frac{m}{4} + \frac{m}{40} = \frac{10m + m}{40} = \frac{11m}{40}$. Mole fraction of lighter gas $(x_1) = \frac{n_1}{n_{total}} = \frac{m/4}{11m/40} = \frac{m}{4} 	imes \frac{40}{11m} = \frac{10}{11}$. Partial pressure of lighter gas $= x_1 	imes P_{total} = \frac{10}{11} 	imes 1.1 \ atm = 1 \ atm$.

Equal amounts of two gases of molecular weights $4$ and $40$ are mixed. The pressure of the mixture is $1.1 \ atm$. What will be the partial pressure of the lighter gas in the mixture (in $atm$)?

Similar Questions

If the rate of diffusion of $A$ is $5$ times the rate of diffusion of $B$,what will be the ratio of the densities of $A$ and $B$?

Why are surgical instruments in hospitals sterilized in an autoclave?

The ratio of rates of diffusion of $SO_2$,$O_2$ and $CH_4$ is

What is saturated vapor pressure?

Which state of matter has a definite volume but no definite shape?

Vedclass Test Series

Exam Paper Generator

Online Exam Module