The amount of ammonium sulphate required for | vedclass

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Question

(B) The molar mass of ammonium sulphate $(NH_4)_2SO_4$ is calculated as: $2 	imes (14 + 4 	imes 1) + 32 + 4 	imes 16 = 2 	imes 18 + 32 + 64 = 36 +

Vedclass · Accepted Answer

$264$

Vedclass · Answer

(B) The molar mass of ammonium sulphate $(NH_4)_2SO_4$ is calculated as: $2 	imes (14 + 4 	imes 1) + 32 + 4 	imes 16 = 2 	imes 18 + 32 + 64 = 36 + 32 + 64 = 132 \, g/mol$. The formula for molarity is: $	ext{Molarity} = \frac{	ext{Weight}}{	ext{Molar mass} 	imes 	ext{Volume in } L}$. Given: $	ext{Molarity} = 1 \, M$,$	ext{Volume} = 2 \, L$,$	ext{Molar mass} = 132 \, g/mol$. Therefore,$	ext{Weight} = 	ext{Molarity} 	imes 	ext{Molar mass} 	imes 	ext{Volume} = 1 	imes 132 	imes 2 = 264 \, gm$.

The amount of ammonium sulphate required for the preparation of $1 \, M$ solution in $2 \, L$ is ............ $gm$.

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