Ethanoic acid on heating with ammonia forms compound $A$ which on treatment with bromine and sodium hydroxide gives compound $B$. Compound $B$ on treatment with $NaNO_2/dil. HCl$ gives compound $C$. The compounds $A, B$ and $C$ respectively are

  • A
    ethanamide,methanamine,methanol
  • B
    propanamide,ethanamine,ethanol
  • C
    $N$-ethylpropanamide,methaneisonitrile,methanamine
  • D
    ethanamine,bromoethane,ethanediazonium chloride

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