Ethanoic acid undergoes Hell-Volhard Zelinsky | vedclass

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Question

(A) The Hell-Volhard Zelinsky $(HVZ)$ reaction is specific to carboxylic acids that contain at least one $\alpha$-hydrogen atom.Ethanoic acid $(CH_3CO

Vedclass · Accepted Answer

presence of $\alpha-H$ atom in ethanoic acid

Vedclass · Answer

(A) The Hell-Volhard Zelinsky $(HVZ)$ reaction is specific to carboxylic acids that contain at least one $\alpha$-hydrogen atom.Ethanoic acid $(CH_3COOH)$ contains an $\alpha$-carbon atom attached to three $\alpha$-hydrogen atoms,allowing it to undergo the $HVZ$ reaction.Methanoic acid $(HCOOH)$ does not have an $\alpha$-carbon atom,and consequently,it lacks $\alpha$-hydrogen atoms,which prevents it from undergoing the $HVZ$ reaction.

Ethanoic acid undergoes Hell-Volhard Zelinsky reaction but methanoic acid does not,because of

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