Ethanol reacts with sodium and forms two prod | vedclass

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Question

(A) When ethanol $(C_2H_5OH)$ reacts with sodium metal $(Na)$,it undergoes a substitution reaction where the hydrogen atom of the hydroxyl group is re

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sodium ethoxide and hydrogen

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(A) When ethanol $(C_2H_5OH)$ reacts with sodium metal $(Na)$,it undergoes a substitution reaction where the hydrogen atom of the hydroxyl group is replaced by sodium.The chemical equation for this reaction is:$2C_2H_5OH + 2Na \rightarrow 2C_2H_5ONa + H_2 \uparrow$In this reaction,$C_2H_5ONa$ (sodium ethoxide) and $H_2$ (hydrogen gas) are formed.Therefore,the correct products are sodium ethoxide and hydrogen.

Ethanol reacts with sodium and forms two products. These are

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