Ethene can be separated from acetylene by pas | vedclass

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Question

(C) Acetylene $(HC \equiv CH)$ is a terminal alkyne with acidic hydrogen atoms. When passed through ammoniacal cuprous chloride $(Cu_2Cl_2)$, it forms

Vedclass · Accepted Answer

ammoniacal $Cu_2Cl_2$

Vedclass · Answer

(C) Acetylene $(HC \equiv CH)$ is a terminal alkyne with acidic hydrogen atoms. When passed through ammoniacal cuprous chloride $(Cu_2Cl_2)$, it forms a red precipitate of copper$(I)$ acetylide: $HC \equiv CH + Cu_2Cl_2 ightarrow CuC \equiv CCu \downarrow (	ext{red ppt}) + 2HCl$. Ethene $(CH_2=CH_2)$ does not react with ammoniacal $Cu_2Cl_2$ and passes through unchanged. Therefore, the mixture can be separated using ammoniacal $Cu_2Cl_2$.

Ethene can be separated from acetylene by passing the mixture through :

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