Ethyl alcohol is heated with concentrated sul | vedclass

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Question

(A) When ethyl alcohol $(C_2H_5OH)$ is heated with concentrated sulphuric acid $(H_2SO_4)$ at $413 \ K$,the reaction undergoes intermolecular dehydrat

Vedclass · Accepted Answer

$C_2H_5-O-C_2H_5$

Vedclass · Answer

(A) When ethyl alcohol $(C_2H_5OH)$ is heated with concentrated sulphuric acid $(H_2SO_4)$ at $413 \ K$,the reaction undergoes intermolecular dehydration to form diethyl ether $(C_2H_5-O-C_2H_5)$.The reaction is as follows:$2C_2H_5OH \xrightarrow{Conc. H_2SO_4, 413 \ K} C_2H_5-O-C_2H_5 + H_2O$At a higher temperature of $443 \ K$,the reaction would instead produce ethene $(CH_2=CH_2)$ via intramolecular dehydration.

Ethyl alcohol is heated with concentrated sulphuric acid at $413 \ K$. The major product is:

Similar Questions

Anisole $\xrightarrow[\text{reflux}]{\text{excess } HI \text{ (conc.)}} \text{ Product}$

Product $(A)$ of this reaction is:

$Ph - \mathop O\limits^{18} - CH_3 \xrightarrow{conc. HI} \text{products}$

What is $Y$ in the following reaction?
$C_2H_5I + NaOC_2H_5 \longrightarrow X + NaI$
$X + 2HI \xrightarrow{\Delta} 2Y + H_2O$

For the given reaction,$A$ and $B$ are respectively:

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