(D) To evaluate $(98)^{2}$,we can express $98$ as $(100 - 2)$.Using the algebraic identity $(a - b)^{2} = a^{2} - 2ab + b^{2}$,where $a = 100$ and $b

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(D) To evaluate $(98)^{2}$,we can express $98$ as $(100 - 2)$.Using the algebraic identity $(a - b)^{2} = a^{2} - 2ab + b^{2}$,where $a = 100$ and $b = 2$:$(100 - 2)^{2} = (100)^{2} - 2(100)(2) + (2)^{2}$$= 10000 - 400 + 4$$= 9600 + 4$$= 9604$.

Class 9 Mathematics Polynomials Mix Examples - Polynomials

Medium

Evaluate $(98)^{2}$.

A
$9801$
B
$9602$
C
$7463$
D
$9604$

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Evaluate $(98)^{2}$.

Similar Questions

From the following polynomials,find out which of them has $(x+1)$ as a factor:$x^{3} + 10x^{2} + 23x + 14$

Factorise $16 x^{2}+40 x y+25 y^{2}$.

Factorise the expression: $\frac{4x^2}{9} - \frac{1}{25}$

Factorise $: x^{3}-125$

Write the coefficient of $x^{2}$ in the following polynomial:$\pi x^{2}-\frac{22}{7} x+3.14$

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From the following polynomials,find out which of them has $(x+1)$ as a factor:
$x^{3} + 10x^{2} + 23x + 14$

Write the coefficient of $x^{2}$ in the following polynomial:
$\pi x^{2}-\frac{22}{7} x+3.14$