(B) To evaluate $(215)^{2}$,we can use the identity $(a + b)^{2} = a^{2} + 2ab + b^{2}$.We can write $215$ as $(200 + 15)$.$(200 + 15)^{2} = (200)^{2}

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(B) To evaluate $(215)^{2}$,we can use the identity $(a + b)^{2} = a^{2} + 2ab + b^{2}$.We can write $215$ as $(200 + 15)$.$(200 + 15)^{2} = (200)^{2} + 2(200)(15) + (15)^{2}$.$= 40000 + 6000 + 225$.$= 46225$.Thus,the correct option is $B$.

Class 9 Mathematics Polynomials Mix Examples - Polynomials

Medium

Evaluate $(215)^{2}$.

A
$44621$
B
$46225$
C
$46925$
D
$47159$

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Mix Examples - Polynomials

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Difficult

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Easy

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Medium

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Factorise $16 x^{2}+40 x y+25 y^{2}$.

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Evaluate $(215)^{2}$.

Similar Questions

Examine whether $2x + 3$ is a factor of $2x^3 + 21x^2 + 67x + 60$ or not.

Write the coefficient of $x^{2}$ in the following polynomial: $\sqrt{3} x^{2}+11$.

If $x+y=12$ and $xy=27$,find the value of $x^{3}+y^{3}$.

Evaluate the following using suitable identities: $(995)^{3}$

Factorise $16 x^{2}+40 x y+25 y^{2}$.

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