Explain the energy of a photon,the kinetic energy of an ejected electron,and the number of photons in the photoelectric effect.

(N/A) The photoelectric effect is governed by Einstein's photoelectric equation:
$E_{\text{photon}} = W + K.E._{\text{max}}$
$h\nu = W + \frac{1}{2}m_e v^2$
Where:
$h\nu$ is the energy of the incident photon.
$W = h\nu_0$ is the work function (minimum energy required to eject an electron).
$\frac{1}{2}m_e v^2$ is the maximum kinetic energy of the ejected photoelectron.
Key relationships:
$1$. Energy of photon: $E = h\nu = \frac{hc}{\lambda}$.
$2$. Kinetic energy of electron: $K.E. = h(\nu - \nu_0)$.
$3$. Number of photons: The intensity of the light beam is directly proportional to the number of photons incident per unit time. $A$ more intense beam contains a larger number of photons,which results in a larger number of photoelectrons being ejected.