Explain the stereochemistry of $S_{N}2$ reaction with a suitable example.

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In the case of optically active alkyl halides,the product formed as a result of $S_{N}2$ reaction has an inverted configuration compared to the reactant.
This occurs because the nucleophile attacks from the side opposite to the one where the halogen atom is present.
For example,when $(-)-2-$bromooctane reacts with a hydroxide ion $(OH^-)$,$(+)-$octan$-2-$ol is formed,where the $-OH$ group occupies the position opposite to the bromide ion.
The reaction is represented as:
$(-)-CH_3CH(Br)C_6H_{13} + OH^- \rightarrow (+)-CH_3CH(OH)C_6H_{13} + Br^-$.
Thus,$S_{N}2$ reactions of optically active halides are accompanied by Walden inversion (inversion of configuration).

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$S_N^1$ reaction is faster in

Which among the following compounds undergoes $SN^2$ reaction most rapidly?

In which of the following cases is the yield via $S_{N}2$ mechanism maximum?

The correct order of $S_N1$ reactivity for the following compounds is:
$(I)$ $CH_3CH_2CH_2CH_2Br$
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$(III)$ $CH_3CH_2CH(Br)CH_3$

$CH_3CH(Br)CH_2CH_3 + \text{alc. } KOH \to$ ?

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