Explain the non-linear shape of $H_2S$ and the non-planar shape of $PCl_3$ using the Valence Shell Electron Pair Repulsion $(VSEPR)$ theory.

(N/A) For $H_2S$: The central atom is $S$. It has $6$ electrons in its valence shell $(_{16}S = 2, 8, 6)$.
Two electrons are shared with two $H$-atoms,and the remaining four electrons form two lone pairs.
There are a total of four electron pairs ($2$ bonding pairs and $2$ lone pairs) around the central atom.
Due to the presence of $2$ lone pairs,the electron geometry is tetrahedral,but the molecular shape is distorted,angular,or bent (non-linear).
For $PCl_3$: The central atom is $P$. It has $5$ electrons in its valence shell $(_{15}P = 2, 8, 5)$.
Three electrons are shared with three $Cl$-atoms,and the remaining two electrons form one lone pair.
There are a total of four electron pairs ($3$ bonding pairs and $1$ lone pair) around the central atom.
Due to the presence of one lone pair,the molecular shape is pyramidal (non-planar).