Explain the shape of $BrF_{5}$.
(N/A) The central atom $Br$ has $7$ electrons in the valence shell.
$5$ of these electrons form bonds with $5$ fluorine atoms,and the remaining $2$ electrons exist as $1$ lone pair.
Thus,the total number of electron pairs is $6$ ($5$ bond pairs and $1$ lone pair).
According to the $VSEPR$ theory,to minimize the repulsion between the lone pair and the bond pairs,the molecule adopts a square pyramidal geometry.
$5$ of these electrons form bonds with $5$ fluorine atoms,and the remaining $2$ electrons exist as $1$ lone pair.
Thus,the total number of electron pairs is $6$ ($5$ bond pairs and $1$ lone pair).
According to the $VSEPR$ theory,to minimize the repulsion between the lone pair and the bond pairs,the molecule adopts a square pyramidal geometry.
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