Explain why ozone $(O_3)$ is thermodynamically less stable than oxygen $(O_2)$?
(N/A) The conversion of ozone $(O_3)$ to oxygen $(O_2)$ is an exothermic process,which means it is accompanied by the liberation of heat $(\Delta H < 0)$.
Additionally,the decomposition of $2$ moles of $O_3$ into $3$ moles of $O_2$ leads to an increase in entropy $(\Delta S > 0)$.
According to the Gibbs free energy equation,$\Delta G = \Delta H - T\Delta S$,both a negative $\Delta H$ and a positive $\Delta S$ result in a large negative value for the Gibbs free energy change $(\Delta G)$.
Since a negative $\Delta G$ indicates a spontaneous process,ozone is thermodynamically less stable than oxygen.
Additionally,the decomposition of $2$ moles of $O_3$ into $3$ moles of $O_2$ leads to an increase in entropy $(\Delta S > 0)$.
According to the Gibbs free energy equation,$\Delta G = \Delta H - T\Delta S$,both a negative $\Delta H$ and a positive $\Delta S$ result in a large negative value for the Gibbs free energy change $(\Delta G)$.
Since a negative $\Delta G$ indicates a spontaneous process,ozone is thermodynamically less stable than oxygen.
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Identify the method used to obtain $SO_2$ gas in industry.
Assertion: $Ozone$ is a powerful oxidising agent in comparison to $O_2$.
Reason: $Ozone$ is diamagnetic but $O_2$ is paramagnetic.
Reason: $Ozone$ is diamagnetic but $O_2$ is paramagnetic.
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View SolutionGiven below are two statements: one is labelled as Assertion $(A)$ and the other is labelled as Reason $(R)$.
Assertion $(A)$ : Both rhombic and monoclinic sulphur exist as $S_8$ while oxygen exists as $O_2$.
Reason $(R)$ : Oxygen forms $p \pi-p \pi$ multiple bonds with itself and other elements having small size and high electronegativity like $C, N$,which is not possible for sulphur.
In the light of the above statements,choose the most appropriate answer from the options given below:
Assertion $(A)$ : Both rhombic and monoclinic sulphur exist as $S_8$ while oxygen exists as $O_2$.
Reason $(R)$ : Oxygen forms $p \pi-p \pi$ multiple bonds with itself and other elements having small size and high electronegativity like $C, N$,which is not possible for sulphur.
In the light of the above statements,choose the most appropriate answer from the options given below:
Why is a Tyndall box used in the manufacture of sulfuric acid by the contact process?
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View SolutionWhat is obtained by the reaction of $SO_2$ with an aqueous solution of sodium hydroxide?
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