Express the number 5005 as a product of its p | vedclass

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Question

(A) To find the prime factors of $5005$,we perform successive division by prime numbers:$1$. Since the last digit is $5$,it is divisible by $5$: $5005

Vedclass · Accepted Answer

$5 	imes 7 	imes 11 	imes 13$

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(A) To find the prime factors of $5005$,we perform successive division by prime numbers:$1$. Since the last digit is $5$,it is divisible by $5$: $5005 \div 5 = 1001$.$2$. Now,divide $1001$ by the next prime number,$7$: $1001 \div 7 = 143$.$3$. Next,divide $143$ by the next prime number,$11$: $143 \div 11 = 13$.$4$. Finally,$13$ is a prime number,so $13 \div 13 = 1$.Therefore,the prime factorization of $5005$ is $5 	imes 7 	imes 11 	imes 13$.

Express the number $5005$ as a product of its prime factors.

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