Factorise:
$6x^{2} + 7x - 3$

(N/A) To factorise the quadratic expression $6x^{2} + 7x - 3$,we use the splitting the middle term method.
We need to find two numbers $p$ and $q$ such that $p + q = 7$ (coefficient of $x$) and $p \times q = 6 \times (-3) = -18$ (product of coefficient of $x^{2}$ and constant term).
Clearly,$9 + (-2) = 7$ and $9 \times (-2) = -18$.
Now,rewrite the middle term $7x$ as $9x - 2x$:
$6x^{2} + 9x - 2x - 3$
Group the terms to factor out common factors:
$= 3x(2x + 3) - 1(2x + 3)$
Finally,factor out the common binomial $(2x + 3)$:
$= (2x + 3)(3x - 1)$