Factorise the following quadratic polynomial by splitting the middle term:
$x^{2}+14x+33$

(N/A) To factorise the quadratic polynomial $x^{2}+14x+33$ by splitting the middle term,we need to find two numbers whose sum is $14$ and whose product is $33$.
$1$. Identify the coefficients: $a=1, b=14, c=33$.
$2$. Find two numbers $p$ and $q$ such that $p+q=14$ and $p \times q=33$.
$3$. The factors of $33$ are $(1, 33)$ and $(3, 11)$.
$4$. Since $3+11=14$,the numbers are $3$ and $11$.
$5$. Rewrite the middle term: $x^{2}+3x+11x+33$.
$6$. Factor by grouping: $x(x+3)+11(x+3)$.
$7$. Final factored form: $(x+3)(x+11)$.