The far point of a myopic eye is 250 , cm. Wh | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For a myopic eye,the far point is at a finite distance $d = 250 \, cm$. To correct this defect,the lens must form an image of an object at infinit

Vedclass · Accepted Answer

$-250 \, cm$

Vedclass · Answer

(A) For a myopic eye,the far point is at a finite distance $d = 250 \, cm$. To correct this defect,the lens must form an image of an object at infinity at the far point of the eye.Using the lens formula: $\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$.Here,$u = \infty$ (object at infinity) and $v = -250 \, cm$ (image formed at the far point).Substituting these values: $\frac{1}{f} = \frac{1}{-250} - \frac{1}{\infty}$.Since $\frac{1}{\infty} = 0$,we get $\frac{1}{f} = -\frac{1}{250}$.Therefore,$f = -250 \, cm$.

The far point of a myopic eye is $250 \, cm$. What is the focal length of the lens required to correct this defect?

Similar Questions

$A$ person suffering from hypermetropia cannot focus on objects closer than $120 \, cm$. To read at a distance of $40 \, cm$,what should be the focal length of the lens required?

Myopia is due to

$A$ person cannot see objects clearly placed at a distance of more than $40 \, cm$. He is advised to use a lens of power:

Myopia can be corrected with the help of a/an ...

The near point of a hypermetropic person is $75\, cm$ from the eye. What is the power of the lens required to enable the person to read clearly a book held at $25\, cm$ from the eye?

Vedclass Test Series

Exam Paper Generator

Online Exam Module