The figure represents an area A = 0.5,m^2 sit | vedclass

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(C) The magnetic flux $\phi$ is given by the formula $\phi = B A \cos 	heta$,where $	heta$ is the angle between the magnetic field vector $\vec{B}$

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$\sqrt{3}/2$

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(C) The magnetic flux $\phi$ is given by the formula $\phi = B A \cos 	heta$,where $	heta$ is the angle between the magnetic field vector $\vec{B}$ and the area vector $\vec{n}$ (normal to the surface).Given that the area makes an angle of $60^o$ with the magnetic field,the angle $	heta$ between the normal to the area and the magnetic field is $	heta = 90^o - 60^o = 30^o$.Substituting the values: $\phi = 2.0 	imes 0.5 	imes \cos(30^o)$.$\phi = 1.0 	imes \frac{\sqrt{3}}{2} = \frac{\sqrt{3}}{2} \, Wb$.

The figure represents an area $A = 0.5\,m^2$ situated in a uniform magnetic field $B = 2.0\,Wb/m^2$. The area makes an angle of $60^o$ with the magnetic field. The value of the magnetic flux through the area is equal to......$Wb$.

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