The figure shows a system of logic gates. Fro | vedclass

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(C) The logic circuit consists of an $OR$ gate,a $NAND$ gate,and a $NOR$ gate. Let the inputs be $X$ and $Y$. The intermediate outputs are $P = \bar{X

Vedclass · Accepted Answer

$X = 1, Y = 0$

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(C) The logic circuit consists of an $OR$ gate,a $NAND$ gate,and a $NOR$ gate. Let the inputs be $X$ and $Y$. The intermediate outputs are $P = \bar{X} + Y$ and $Q = \overline{X \cdot \bar{Y}}$. The final output is $R = \overline{P + Q}$.The truth table is as follows:$X$$Y$$\bar{X}$$\bar{Y}$$P = \bar{X} + Y$$Q = \overline{X \cdot \bar{Y}}$$R = \overline{P + Q}$$0$$0$$1$$1$$1$$1$$0$$0$$1$$1$$0$$1$$1$$0$$1$$0$$0$$1$$0$$0$$1$$1$$1$$0$$0$$1$$1$$0$From the table,it is clear that to obtain a high output $(1)$ at $R$,the inputs must be $X = 1$ and $Y = 0$.

The figure shows a system of logic gates. From the study of the truth table,it can be found that to produce a high output $(1)$ at $R$,we must have

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