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(C) The magnetic field produced by an infinite current sheet is uniform and directed parallel to the sheet. According to the right-hand rule,for a cur

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Square loop will remain in translational equilibrium

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(C) The magnetic field produced by an infinite current sheet is uniform and directed parallel to the sheet. According to the right-hand rule,for a current flowing out of the plane (represented by dots),the magnetic field $B$ points upwards in the region to the right of the sheet.In the square loop,the current flows in a clockwise direction. Let the sides of the loop be $l_1$ (near the sheet),$l_2$ (far from the sheet),$l_3$ (top),and $l_4$ (bottom).The magnetic force on a wire is given by $F = I(L 	imes B)$.$1$. For the top and bottom sides ($l_3$ and $l_4$),the forces are equal and opposite,resulting in a net force of zero in the vertical direction.$2$. For the side $l_1$ (near the sheet),the current flows downwards. The force $F_1 = I(l_1 	imes B)$ is directed away from the sheet (repulsive).$3$. For the side $l_2$ (far from the sheet),the current flows upwards. The force $F_2 = I(l_2 	imes B)$ is directed towards the sheet (attractive).Since the magnetic field $B$ is uniform,the magnitudes of the forces on the vertical sides are equal $(F_1 = F_2)$. However,because the loop is in a uniform magnetic field,the net force on the loop is zero. Thus,the loop remains in translational equilibrium.

The figure shows a cross-section of an infinite metal sheet carrying an electric current along its surface. The current per unit length is $J$. $A$ current-carrying square loop is placed nearby the metal sheet such that the plane of the square is perpendicular to the plane of the sheet. Then:

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