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(C) $1$. Average velocity is defined as the total displacement divided by the total time interval: $v_{avg} = \frac{\Delta x}{\Delta t}$.$2$. From the

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(C) $1$. Average velocity is defined as the total displacement divided by the total time interval: $v_{avg} = \frac{\Delta x}{\Delta t}$.$2$. From the graph,at $t=0 \,s$,$x=0 \,m$. At $t=6 \,s$,$x=0 \,m$.$3$. Total displacement $\Delta x = x(6) - x(0) = 0 - 0 = 0 \,m$.$4$. Therefore,average velocity $v_{avg} = \frac{0}{6} = 0 \,m/s$.$5$. Instantaneous velocity is the slope of the $x-t$ graph at a given time: $v = \frac{dx}{dt}$.$6$. At $t=3 \,s$,the particle is in the interval $t=1 \,s$ to $t=4 \,s$,where the position $x$ is constant at $10 \,m$.$7$. Since the position is constant,the slope of the graph is zero. Thus,the instantaneous velocity at $t=3 \,s$ is $0 \,m/s$.

The figure shows the graph of the $x$-coordinate of a particle moving along the $x$-axis as a function of time. The average velocity during $t=0$ to $6 \,s$ and the instantaneous velocity at $t=3 \,s$ respectively,will be

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