The final product 'C' is? | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Step $1$: Reaction of $1,2$-dimethylcyclohexane with $Br_2/h
u$ (free radical bromination) leads to the formation of $1$-bromo-$1,2$-dimethylcycl

Vedclass · Accepted Answer

Octane$-2,7-$dione

Vedclass · Answer

(B) Step $1$: Reaction of $1,2$-dimethylcyclohexane with $Br_2/h
u$ (free radical bromination) leads to the formation of $1$-bromo-$1,2$-dimethylcyclohexane (compound $A$).Step $2$: Treatment of $A$ with $CH_3ONa$ (a strong base) results in dehydrobromination via an $E2$ mechanism to form $1,2$-dimethylcyclohex$-1-$ene (compound $B$).Step $3$: Ozonolysis of $1,2$-dimethylcyclohex$-1-$ene $(B)$ followed by reductive workup with $Zn/H_2O$ cleaves the double bond to yield $2,7$-octanedione (compound $C$).

The final product $'C'$ is?

Similar Questions

Dilute aqueous $KMnO_4$ at room temperature reacts with $R-CH=CH-R$ to give:

Indicate the organic structure for the product expected when $2-$methylpropene is heated with acetyl chloride in the presence of anhydrous zinc chloride.

Alkenes $(C=C)$ and carbonyl compounds $(C=O)$ both contain a $\pi$-bond,but alkenes show electrophilic addition reactions,whereas carbonyl compounds show nucleophilic addition reactions. Explain.

$CH_3-CH_2-CH=CH_2 \xrightarrow[CCl_4]{Br_2} \text{Product}$

What is obtained by the dehydrohalogenation of allyl chloride?

Vedclass Test Series

Exam Paper Generator

Online Exam Module