(B) Let $\log _{3 / 2} 3.375 = x$.By the definition of logarithm,this can be written as $(3 / 2)^x = 3.375$.We know that $3 / 2 = 1.5$.Now,calculate $

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(B) Let $\log _{3 / 2} 3.375 = x$.By the definition of logarithm,this can be written as $(3 / 2)^x = 3.375$.We know that $3 / 2 = 1.5$.Now,calculate $1.5^3 = 1.5 \times 1.5 \times 1.5 = 2.25 \times 1.5 = 3.375$.So,$(1.5)^x = (1.5)^3$.Comparing the exponents,we get $x = 3$.