Find a number nearest to 9231 which is exactl | vedclass

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Question

(A) number divisible by both $3$ and $11$ must be divisible by their least common multiple,which is $33.$ To find the nearest number,we divide $9231$

Vedclass · Accepted Answer

$9240$

Vedclass · Answer

(A) number divisible by both $3$ and $11$ must be divisible by their least common multiple,which is $33.$ To find the nearest number,we divide $9231$ by $33.$ $9231 \div 33 = 279$ with a remainder of $24.$ Since the remainder $24$ is greater than half of the divisor $(33 / 2 = 16.5)$,the next multiple of $33$ is closer to $9231$ than the current quotient's multiple. The nearest number is $9231 + (33 - 24) = 9231 + 9 = 9240.$

Find a number nearest to $9231$ which is exactly divisible by $3$ as well as by $11.$

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