Find a quadratic polynomial with the given numbers as the sum and product of its zeroes respectively: $4, 1$.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(A) Let the quadratic polynomial be $p(x) = ax^2 + bx + c$,where $\alpha$ and $\beta$ are its zeroes.
The sum of the zeroes is given by $\alpha + \beta = 4 = \frac{4}{1} = \frac{-b}{a}$.
The product of the zeroes is given by $\alpha \times \beta = 1 = \frac{1}{1} = \frac{c}{a}$.
By comparing the ratios,if we assume $a = 1$,then $b = -4$ and $c = 1$.
Substituting these values into the general form $ax^2 + bx + c$,we get the quadratic polynomial $x^2 - 4x + 1$.

Explore More

Similar Questions

Divide $3x^{2}-x^{3}-3x+5$ by $x-1-x^{2}$ and verify the division algorithm.

Difficult
View Solution

Divide the polynomial $p(x)$ by the polynomial $g(x)$ and find the quotient and remainder in each of the following:
$p(x) = x^{4} - 5x + 6, \quad g(x) = 2 - x^{2}$

Difficult
View Solution

The graph of $y=p(x)$ is given below for a polynomial $p(x)$. Find the number of zeroes of $p(x)$.

Look at the graph given below. It is the graph of $y=p(x)$ where $p(x)$ is a polynomial. Find the number of zeroes of $p(x)$.

Verify that $3, -1, -\frac{1}{3}$ are the zeroes of the cubic polynomial $p(x) = 3x^3 - 5x^2 - 11x - 3$,and then verify the relationship between the zeroes and the coefficients.

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo