Find four rational numbers between $\frac{2}{9}$ and $\frac{2}{7}$.

(N/A) To find rational numbers between $\frac{2}{9}$ and $\frac{2}{7}$,we first make their denominators equal by finding the least common multiple of $9$ and $7$,which is $63$.
$\frac{2}{9} = \frac{2 \times 7}{9 \times 7} = \frac{14}{63}$
$\frac{2}{7} = \frac{2 \times 9}{7 \times 9} = \frac{18}{63}$
Since there are only three integers between $14$ and $18$ $(15, 16, 17)$,we multiply the numerator and denominator by a larger factor,say $2$,to get more space.
$\frac{14}{63} = \frac{14 \times 2}{63 \times 2} = \frac{28}{126}$
$\frac{18}{63} = \frac{18 \times 2}{63 \times 2} = \frac{36}{126}$
Now,we can choose any four rational numbers between $\frac{28}{126}$ and $\frac{36}{126}$,such as $\frac{29}{126}, \frac{30}{126}, \frac{31}{126}, \text{ and } \frac{32}{126}$.
Simplifying these,we get $\frac{29}{126}, \frac{5}{21}, \frac{31}{126}, \text{ and } \frac{16}{63}$.