Find out K_a for the acid when the degree of | vedclass

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(B) The degree of hydrolysis $h$ for a salt of a weak acid and strong base is given by $h = \sqrt{\frac{K_h}{C}}$.Here,$K_h = \frac{K_w}{K_a}$,so $h =

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$10^{-9}$

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(B) The degree of hydrolysis $h$ for a salt of a weak acid and strong base is given by $h = \sqrt{\frac{K_h}{C}}$.Here,$K_h = \frac{K_w}{K_a}$,so $h = \sqrt{\frac{K_w}{K_a 	imes C}}$.Given $h = 1 \% = 0.01 = 10^{-2}$,$C = 0.1 \ M$,and $K_w = 10^{-14}$.Substituting the values: $10^{-2} = \sqrt{\frac{10^{-14}}{K_a 	imes 0.1}}$.Squaring both sides: $10^{-4} = \frac{10^{-14}}{K_a 	imes 0.1}$.$K_a = \frac{10^{-14}}{10^{-4} 	imes 0.1} = \frac{10^{-14}}{10^{-5}} = 10^{-9}$.

Find out $K_a$ for the acid when the degree of hydrolysis of $0.1 \ M \ CH_3COONa$ is $1 \ \%$.

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