Find the major product for the following reac | vedclass

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Question

(A) The reaction involves the acid-catalyzed dehydration of an alcohol. $1$. Protonation of the hydroxyl group occurs to form a good leaving group $(-

Vedclass · Accepted Answer

$1,2-$dimethylcyclohexene

Vedclass · Answer

(A) The reaction involves the acid-catalyzed dehydration of an alcohol. $1$. Protonation of the hydroxyl group occurs to form a good leaving group $(-OH_2^+)$. $2$. Loss of water generates a secondary carbocation. $3$. $A$ ring expansion occurs because the five-membered ring with a carbocation adjacent to it is less stable than a six-membered ring. The bond from the ring shifts to the carbocation center,resulting in a more stable six-membered ring with a carbocation at the adjacent position. $4$. Finally,deprotonation occurs to form the most stable alkene,which is the more substituted alkene (Saytzeff product). Thus,the major product is $1,2$-dimethylcyclohexene.

Find the major product for the following reaction.

Similar Questions

Optically active $3-$methylpent$-1-$en$-3-$ol loses its optical activity after standing in water containing a few drops of acid,mainly due to the formation of:

$CH_3-CH(CH_3)-CH(OH)-CH_3$ $\xrightarrow[350^\circ C]{Al_2O_3} (A)$ $\xrightarrow[(ii) AgOH]{(i) HI} (B)$
Product $(B)$ of the above reaction is:

$CH_3 CH_2 OH \underset{\text{step-}1}{\stackrel{Cl_2}{\longrightarrow}} CH_3 CHO$ $\underset{\text{step-}2}{\stackrel{3 Cl_2}{\longrightarrow}} Cl_3 CCHO$
In the above reactions,the role of $Cl_2$ in step-$1$ and step-$2$ respectively is:

Which is the best method to prepare cyclohexene from cyclohexanol?

Which one of the following is a secondary alcohol?

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