Find out the major product formed from the fo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction involves the nucleophilic substitution of bromine atoms by dimethylamine $(Me_2NH)$.First,one $Me_2NH$ molecule attacks the allylic p

Vedclass · Accepted Answer

$3,4-$bis(dimethylamino)cyclopent$-1-$ene

Vedclass · Answer

(A) The reaction involves the nucleophilic substitution of bromine atoms by dimethylamine $(Me_2NH)$.First,one $Me_2NH$ molecule attacks the allylic position,displacing one $Br^-$ ion.Then,the lone pair on the nitrogen atom of the newly attached dimethylamino group participates in the formation of an aziridinium ion intermediate by displacing the second $Br^-$ ion.Finally,a second molecule of $Me_2NH$ attacks the aziridinium ring,opening it to form the final product,which is $3,4$-bis(dimethylamino)cyclopent-$1$-ene.

Find out the major product formed from the following reaction. $[Me = -CH_3]$

Similar Questions

The major product $[B]$ in the following sequence of reactions is
$CH_3-C(CH(CH_3)_2)=CH-CH_2CH_3$ $\xrightarrow[(i) B_2H_6]{(ii) H_2O_2, OH^{-}} [A]$ $\xrightarrow[\Delta]{dil. H_2SO_4} [B]$

The total number of alkyl bromides (including stereoisomers) formed in the reaction $(CH_3)_3C-CH=CH_2 + HBr \rightarrow$ will be

Propene on hydroboration followed by oxidation with alkaline peroxide forms.

Identify $X, Y$ and $Z$ in the following reactions:

The product $(A)$ of the given oxymercuration-demercuration reaction is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module