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Question

(A) The reaction of an alkyl halide with magnesium in the presence of an ether solvent like $T.H.F$ (Tetrahydrofuran) forms a Grignard reagent.$CH_2=C

Vedclass · Accepted Answer

$CH_2=CH-CH_2-CH_2-CH=CH_2$

Vedclass · Answer

(A) The reaction of an alkyl halide with magnesium in the presence of an ether solvent like $T.H.F$ (Tetrahydrofuran) forms a Grignard reagent.$CH_2=CH-CH_2Br + Mg \xrightarrow{T.H.F} CH_2=CH-CH_2MgBr$This Grignard reagent $(CH_2=CH-CH_2MgBr)$ can react with the remaining unreacted alkyl halide $(CH_2=CH-CH_2Br)$ via a Wurtz-type coupling reaction.$CH_2=CH-CH_2MgBr + CH_2=CH-CH_2Br \rightarrow CH_2=CH-CH_2-CH_2-CH=CH_2 + MgBr_2$The product formed is $1,5-hexadiene$ $(CH_2=CH-CH_2-CH_2-CH=CH_2)$.

Find out the major product of the following reaction:
$2 \text{ mole } CH_2=CH-CH_2Br \xrightarrow{Mg, T.H.F}$

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Find out the major product of the following reaction:$2 \text{ mole } CH_2=CH-CH_2Br \xrightarrow{Mg, T.H.F}$