Find the potential difference between A and B | vedclass

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(D) In the steady state,the capacitors act as open circuits,meaning no current flows through the branches containing capacitors. Since there is no cur

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$100$

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(D) In the steady state,the capacitors act as open circuits,meaning no current flows through the branches containing capacitors. Since there is no current flowing in the circuit $(I = 0)$,there is no voltage drop across the resistors ($200 \ \Omega$ and $10 \ \Omega$). Therefore,the entire potential difference of the battery $(100 \ V)$ appears across the parallel branches connected to the battery terminals. Let the potential of the bottom wire be $0 \ V$. Then the potential of the top wire is $100 \ V$. The branch containing $A$ and $B$ is connected in parallel to the battery. Since no current flows,the potential at point $A$ is the same as the potential of the left terminal of the battery,and the potential at point $B$ is the same as the potential of the right terminal of the battery. Thus,the potential difference $V_{AB} = V_A - V_B = 100 \ V$.

Find the potential difference between $A$ and $B$ in the given circuit in the steady state. (in $V$)

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