Find the 45^{th} term of the A.P. 13, 8, 3, - | vedclass

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Question

(C) The given $A.P.$ is $13, 8, 3, -2, \ldots$Here,the first term $a = 13$.The common difference $d = 8 - 13 = -5$.We need to find the $45^{th}$ term,

Vedclass · Accepted Answer

$-207$

Vedclass · Answer

(C) The given $A.P.$ is $13, 8, 3, -2, \ldots$Here,the first term $a = 13$.The common difference $d = 8 - 13 = -5$.We need to find the $45^{th}$ term,denoted by $a_{45}$.The formula for the $n^{th}$ term of an $A.P.$ is $a_n = a + (n - 1)d$.Substituting the values $a = 13$,$n = 45$,and $d = -5$:$a_{45} = 13 + (45 - 1)(-5)$$a_{45} = 13 + (44)(-5)$$a_{45} = 13 - 220$$a_{45} = -207$.Therefore,the $45^{th}$ term is $-207$.

Find the $45^{th}$ term of the $A.P.$ $13, 8, 3, -2, \ldots$

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