Find the HCF of 12,15,and 21. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To find the $HCF$ (Highest Common Factor) of $12$,$15$,and $21$,we first find the prime factorization of each number:$12 = 2^2 	imes 3^1$$15 = 3^

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(A) To find the $HCF$ (Highest Common Factor) of $12$,$15$,and $21$,we first find the prime factorization of each number:$12 = 2^2 	imes 3^1$$15 = 3^1 	imes 5^1$$21 = 3^1 	imes 7^1$The $HCF$ is the product of the smallest power of each common prime factor present in the numbers.The only common prime factor is $3$,and its smallest power is $3^1$.Therefore,$HCF$ $(12, 15, 21) = 3$.

Find the $HCF$ of $12$,$15$,and $21$.

Similar Questions

Prove that $7\sqrt{5}$ is an irrational number.

The decimal expansion of $\frac{15}{2^2}$ terminates after how many decimal places?

The last digit of $5^{25}$ is . . . . . . .

The decimal representation of $\frac{7}{2^3 \cdot 5^4}$ will have how many digits after the decimal point?

The largest $4$-digit integer divisible by $95$ is . . . . . . .

Vedclass Test Series

Exam Paper Generator

Online Exam Module