Find the HCF(510, 92). | vedclass

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Question

(D) To find the $HCF(510, 92)$,we perform prime factorization of both numbers:$510 = 2 	imes 3 	imes 5 	imes 17$$92 = 2 	imes 2 	imes 23 = 2^2

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(D) To find the $HCF(510, 92)$,we perform prime factorization of both numbers:$510 = 2 	imes 3 	imes 5 	imes 17$$92 = 2 	imes 2 	imes 23 = 2^2 	imes 23$The common prime factor with the lowest exponent is $2^1 = 2$.Therefore,$HCF(510, 92) = 2$.

Find the $HCF(510, 92)$.

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