Find the HCF of 12, 15,and 21. | vedclass

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Question

(A) To find the $HCF$ of $12, 15$,and $21$,we first find the prime factorization of each number:$12 = 2^2 	imes 3^1$$15 = 3^1 	imes 5^1$$21 = 3^1

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(A) To find the $HCF$ of $12, 15$,and $21$,we first find the prime factorization of each number:$12 = 2^2 	imes 3^1$$15 = 3^1 	imes 5^1$$21 = 3^1 	imes 7^1$The $HCF$ is the product of the smallest power of each common prime factor.The only common prime factor is $3$,and its smallest power is $3^1$.Therefore,$	ext{HCF}(12, 15, 21) = 3$.

$Q.1.$ $HCF$ of $25$ and $10$	$A. 5$
$Q.2.$ $LCM$ of $17$ and $11$	$B. 187$

Find the $HCF$ of $12, 15$,and $21$.

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