Find the approximate number of molecules cont | vedclass

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(A) Given:Volume $V = 7 	ext{ L} = 7 	imes 10^{-3} 	ext{ m}^{3}$Temperature $T = 0^{\circ}C = 273 	ext{ K}$Pressure $P = 1.3 	imes 10^{5} 	ext{

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$2.4 	imes 10^{23}$

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(A) Given:Volume $V = 7 	ext{ L} = 7 	imes 10^{-3} 	ext{ m}^{3}$Temperature $T = 0^{\circ}C = 273 	ext{ K}$Pressure $P = 1.3 	imes 10^{5} 	ext{ Pa}$Universal gas constant $R = 8.314 	ext{ J/(mol K)}$Using the ideal gas equation $PV = nRT$,we find the number of moles $n$:$n = \frac{PV}{RT} = \frac{1.3 	imes 10^{5} 	imes 7 	imes 10^{-3}}{8.314 	imes 273} \approx 0.4 	ext{ moles}$The number of molecules $N$ is given by $N = n 	imes N_{A}$,where $N_{A} = 6.022 	imes 10^{23} 	ext{ molecules/mol}$.$N = 0.4 	imes 6.022 	imes 10^{23} \approx 2.4 	imes 10^{23} 	ext{ molecules}$.

Find the approximate number of molecules contained in a vessel of volume $7 \text{ litres}$ at $0^{\circ}C$ and a pressure of $1.3 \times 10^{5} \text{ Pa}$.

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