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(D) The area of a triangle with vertices $(x_1, y_1)$,$(x_2, y_2)$,and $(x_3, y_3)$ is given by the formula:Area $= \frac{1}{2} |x_1(y_2 - y_3) + x_2(

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$2$

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(D) The area of a triangle with vertices $(x_1, y_1)$,$(x_2, y_2)$,and $(x_3, y_3)$ is given by the formula:Area $= \frac{1}{2} |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|$Given vertices are $A(5, 2)$,$B(4, 7)$,and $C(7, -4)$.Substituting the values into the formula:Area $= \frac{1}{2} |5(7 - (-4)) + 4(-4 - 2) + 7(2 - 7)|$Area $= \frac{1}{2} |5(11) + 4(-6) + 7(-5)|$Area $= \frac{1}{2} |55 - 24 - 35|$Area $= \frac{1}{2} |55 - 59|$Area $= \frac{1}{2} |-4|$Area $= \frac{1}{2} 	imes 4 = 2$ square units.

Find the area of a triangle formed by the points $A(5, 2)$,$B(4, 7)$,and $C(7, -4)$ (in square units).

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