Find the area of the flower bed (with semi-circular ends) shown in the figure.
(N/A) The flower bed consists of a central rectangular part and two semi-circular ends.
The length of the rectangular part is $38 \, cm$ and its breadth is $10 \, cm$.
Area of the rectangle $= \text{Length} \times \text{Breadth} = 38 \times 10 = 380 \, cm^2$.
The two semi-circular ends together form one complete circle with a diameter of $10 \, cm$.
Radius of the circle $(r) = \frac{10}{2} = 5 \, cm$.
Area of the two semi-circles $= \pi r^2 = \pi \times (5)^2 = 25 \pi \, cm^2$.
Total area of the flower bed $= \text{Area of rectangle} + \text{Area of two semi-circles} = (380 + 25 \pi) \, cm^2$.
The length of the rectangular part is $38 \, cm$ and its breadth is $10 \, cm$.
Area of the rectangle $= \text{Length} \times \text{Breadth} = 38 \times 10 = 380 \, cm^2$.
The two semi-circular ends together form one complete circle with a diameter of $10 \, cm$.
Radius of the circle $(r) = \frac{10}{2} = 5 \, cm$.
Area of the two semi-circles $= \pi r^2 = \pi \times (5)^2 = 25 \pi \, cm^2$.
Total area of the flower bed $= \text{Area of rectangle} + \text{Area of two semi-circles} = (380 + 25 \pi) \, cm^2$.
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