Find the charge in steady state of the capaci | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In steady state,the capacitor acts as an open circuit,meaning no current flows through it.The circuit consists of a $12 \ V$ battery,a $100 \ \Ome

Vedclass · Accepted Answer

$8$

Vedclass · Answer

(D) In steady state,the capacitor acts as an open circuit,meaning no current flows through it.The circuit consists of a $12 \ V$ battery,a $100 \ \Omega$ resistor,and a $200 \ \Omega$ resistor in series.The total resistance of the circuit is $R_{eq} = 100 \ \Omega + 200 \ \Omega = 300 \ \Omega$.The current flowing through the circuit is $I = \frac{V}{R_{eq}} = \frac{12 \ V}{300 \ \Omega} = 0.04 \ A$.The voltage across the $200 \ \Omega$ resistor (which is in parallel with the capacitor) is $V_c = I 	imes 200 \ \Omega = 0.04 \ A 	imes 200 \ \Omega = 8 \ V$.The charge on the capacitor is given by $q = C 	imes V_c$.Substituting the values,$q = 1 \ nF 	imes 8 \ V = 8 \ nC$.

Find the charge in steady state of the capacitor. (in $nC$)

Similar Questions

The time in seconds required to produce a potential difference of $20 \ V$ across a capacitor of $1000 \ \mu F$ when it is charged at a steady rate of $200 \ \mu C/s$ is

$A$ $2500 \,\mu F$ capacitor is charged through a $1 \,k\Omega$ resistor by a $12 \,V$ d.c. source. The voltage across the capacitor after $5 \,s$ is ..... $V$.

In the circuit shown in the figure,$R = \sqrt{\frac{L}{C}}$. Switch $S$ is closed at time $t = 0$. The current through $C$ and $L$ would be equal after a time $t$ equal to

$A$ $1 \mu F$ capacitor $C$ is connected to a battery of $10 V$ through a resistance of $1 \text{ M}\Omega$. The voltage across $C$ after $1 \text{ s}$ is approximately: (in $V$)

When the key $K$ is pressed at time $t = 0$, which of the following statements about the current $I$ in the resistor $AB$ of the given circuit is true?

Vedclass Test Series

Exam Paper Generator

Online Exam Module