Find the distance from the origin to the point $(6, 6, 7)$.

If the sum of the squares of the distances of the point $P(x, y, z)$ from the coordinate axes is $242$,then the distance of the point $P$ from the origin is . . . . . . units.

How far apart are the points $(2,0,0)$ and $(-3,0,0)$?

In the figure,if $P$ is $(2, 4, 5)$,find the coordinates of $F$.

If $d_1, d_2, d_3$ are the distances of the point $(1, 2, 3)$ from the $X, Y, Z$-coordinate axes respectively,then $2 d_2^2 + d_3^2 + 1 =$

Find the distance between the points $P(1, -3, 4)$ and $Q(-4, 1, 2)$.