Find the equation of the circle with centre $(0,2)$ and radius $2$.

The equation of the circle with centre $(2, -3)$ and touching the $X$-axis is

The radius of a circle which touches the $y$-axis at $(0,3)$ and cuts an intercept of $8$ units with the $x$-axis is

The sides of a rectangle are given by $x = \pm a$ and $y = \pm b$. Then the equation of the circle passing through the vertices of the rectangle is

If the equation of the circle having its centre in the second quadrant touches the coordinate axes and also the line $\frac{x}{5}+\frac{y}{12}=1$ is $x^2+y^2+2 \lambda x-2 \lambda y+\lambda^2=0$,then $\lambda=$

$A$ circle passes through the point $(1, -2)$ and touches the $x$-axis at $(3, 0)$. Through which of the following points does it also pass?