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(A) The equation of a line passing through a point $(x_0, y_0)$ with slope $m$ is given by the point-slope form: $(y-y_0) = m(x-x_0)$.Given point $(x_

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$x-2y+10=0$

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(A) The equation of a line passing through a point $(x_0, y_0)$ with slope $m$ is given by the point-slope form: $(y-y_0) = m(x-x_0)$.Given point $(x_0, y_0) = (-4, 3)$ and slope $m = \frac{1}{2}$.Substituting these values into the formula:$(y-3) = \frac{1}{2}(x - (-4))$$(y-3) = \frac{1}{2}(x+4)$Multiply both sides by $2$:$2(y-3) = x+4$$2y-6 = x+4$Rearranging the terms to the form $Ax+By+C=0$:$x - 2y + 4 + 6 = 0$$x - 2y + 10 = 0$.

Find the equation of the line which passes through the point $(-4, 3)$ with slope $\frac{1}{2}$.

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