Find the equivalent resistance of the following circuit.

$(7.5 \, \Omega)$ The circuit consists of resistors in series and parallel combinations.
First, consider the two $2 \, \Omega$ resistors connected in parallel. Let their combined resistance be $R_{P1}$.
$\frac{1}{R_{P1}} = \frac{1}{2} + \frac{1}{2} = 1 \implies R_{P1} = 1 \, \Omega$.
Next, consider the two $1 \, \Omega$ resistors connected in parallel. Let their combined resistance be $R_{P2}$.
$\frac{1}{R_{P2}} = \frac{1}{1} + \frac{1}{1} = 2 \implies R_{P2} = 0.5 \, \Omega$.
Finally, the total equivalent resistance $R$ of the circuit is the sum of the series components:
$R = 3 \, \Omega + 3 \, \Omega + R_{P1} + R_{P2}$
$R = 6 \, \Omega + 1 \, \Omega + 0.5 \, \Omega = 7.5 \, \Omega$.