Find the fraction which bears the same ratio | vedclass

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Question

(B) Let the required fraction be $x$.According to the problem,the ratio of $x$ to $\frac{1}{27}$ is equal to the ratio of $\frac{3}{7}$ to $\frac{5}{9

Vedclass · Accepted Answer

$\frac{1}{35}$

Vedclass · Answer

(B) Let the required fraction be $x$.According to the problem,the ratio of $x$ to $\frac{1}{27}$ is equal to the ratio of $\frac{3}{7}$ to $\frac{5}{9}$.This can be written as: $x : \frac{1}{27} = \frac{3}{7} : \frac{5}{9}$.Using the property of ratios,we have: $\frac{x}{1/27} = \frac{3/7}{5/9}$.Simplifying the right side: $\frac{3}{7} 	imes \frac{9}{5} = \frac{27}{35}$.So,$x 	imes 27 = \frac{27}{35}$.$x = \frac{27}{35} 	imes \frac{1}{27}$.$x = \frac{1}{35}$.Thus,the required fraction is $\frac{1}{35}$.

Find the fraction which bears the same ratio to $\frac{1}{27}$ that $\frac{3}{7}$ does to $\frac{5}{9}$.

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