Find the greatest fraction among the fraction | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) We can express each fraction as $1 - \frac{1}{n}$:$\frac{17}{18} = 1 - \frac{1}{18}$$\frac{21}{22} = 1 - \frac{1}{22}$$\frac{26}{27} = 1 - \frac{1

Vedclass · Accepted Answer

$\frac{36}{37}$

Vedclass · Answer

(D) We can express each fraction as $1 - \frac{1}{n}$:$\frac{17}{18} = 1 - \frac{1}{18}$$\frac{21}{22} = 1 - \frac{1}{22}$$\frac{26}{27} = 1 - \frac{1}{27}$$\frac{36}{37} = 1 - \frac{1}{37}$Since the numerators are the same $(1)$,the fraction with the largest denominator is the smallest value.Thus,$\frac{1}{18} > \frac{1}{22} > \frac{1}{27} > \frac{1}{37}$.Subtracting these from $1$,the smallest value subtracted results in the largest fraction:$1 - \frac{1}{18} Therefore,the greatest fraction is $\frac{36}{37}$.

Find the greatest fraction among the fractions $\frac{17}{18}, \frac{21}{22}, \frac{26}{27}$ and $\frac{36}{37}$?

Similar Questions

The sum of nine consecutive odd numbers of Set $A$ is $621$. What is the sum of a different set of six consecutive even numbers whose lowest number is $15$ more than the lowest number of Set $A$?

Which one is the largest among the fractions $\frac{5}{113}, \frac{7}{120}, \frac{13}{145}$ and $\frac{17}{160}$?

$26 \times 451 - ? = 5109$

$A$ number when divided by $221$ gives a remainder $43$. What remainder will be obtained by dividing the same number by $17$?

$\frac{3}{5}$ th of $24 \%$ of $500 - 32 = ?$

Vedclass Test Series

Exam Paper Generator

Online Exam Module