Find the least number of complete years in wh | vedclass

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(A) Given: Principal $(P) = Rs. 1500$,Rate $(R) = 25 \% 	ext{ per annum}$.We need to find the minimum number of years $(n)$ such that the amount $(A)

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(A) Given: Principal $(P) = Rs. 1500$,Rate $(R) = 25 \% 	ext{ per annum}$.We need to find the minimum number of years $(n)$ such that the amount $(A)$ becomes more than double the principal,i.e.,$A > 2P$.The formula for compound interest is $A = P(1 + R/100)^n$.Substituting the values: $P(1 + 25/100)^n > 2P$.Dividing both sides by $P$: $(1 + 1/4)^n > 2$,which simplifies to $(5/4)^n > 2$.Calculating for different values of $n$:For $n = 1: (1.25)^1 = 1.25 For $n = 2: (1.25)^2 = 1.5625 For $n = 3: (1.25)^3 = 1.953125 For $n = 4: (1.25)^4 = 2.44140625 > 2$.Thus,the least number of complete years required is $4$.

Find the least number of complete years in which a sum of $Rs. 1500$ at $25 \%$ compound interest will be more than double.

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