Find the major product in the given reaction:

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction of an ether with $HI$ proceeds via an $SN^1$ mechanism when one of the alkyl groups is tertiary. $1$. The oxygen atom of the ether is

Vedclass · Accepted Answer

$CH_3-CH_2-CH_2-OH$ and $CH_3-CH_2-C(CH_3)_2-I$

Vedclass · Answer

(B) The reaction of an ether with $HI$ proceeds via an $SN^1$ mechanism when one of the alkyl groups is tertiary. $1$. The oxygen atom of the ether is protonated by $H^+$ from $HI$ to form an oxonium ion. $2$. The bond between the oxygen and the tertiary carbon breaks to form a stable tertiary carbocation $(CH_3-CH_2-C^+(CH_3)_2)$ and a propanol molecule $(CH_3-CH_2-CH_2-OH)$. $3$. The iodide ion $(I^-)$ then attacks the tertiary carbocation to form the tertiary alkyl iodide $(CH_3-CH_2-C(CH_3)_2-I)$. Thus,the products are $CH_3-CH_2-CH_2-OH$ and $CH_3-CH_2-C(CH_3)_2-I$.

Column-$I$	Column-$II$
$(A)$ $CH_3-O-CH_3$	$(1)$ $C_6H_5OH + CH_3I$
$(B)$ $(CH_3)_2CH-O-CH_3$	$(2)$ $(CH_3)_3C-I + CH_3OH$
$(C)$ $(CH_3)_3C-O-CH_3$	$(3)$ $C_6H_5I + CH_3OH$
$(D)$ $C_6H_5-O-CH_3$	$(4)$ $CH_3OH + CH_3I$
	$(5)$ $(CH_3)_2CHOH + CH_3I$
	$(6)$ $(CH_3)_2CH-I + CH_3OH$
	$(7)$ $(CH_3)_3COH + CH_3I$

Similar Questions

For the given reaction,$A$ and $B$ are respectively:

Identify the products $R$ and $S$ in the reaction sequence given:
$(CH_3)_3 COH$ $\xrightarrow{Na} P$ $\xrightarrow{CH_3 Br} Q$ $\xrightarrow[\Delta]{HI} R + S$

The major products $C$ and $D$ formed in the following reaction are:
$CH_{3}CH_{2}CH_{2}OC(CH_{3})_{3} \xrightarrow[\Delta]{\text{excess } HI} C + D$

The hybridisation of oxygen in diethyl ether is

Vedclass Test Series

Exam Paper Generator

Online Exam Module